x^2+0.0032x-0.0016=0

Solution for x^2+0.0032x-0.0016=0 equation:

x^2+0.0032x-0.0016=0

a = 1; b = 0.0032; c = -0.0016;
Δ = b2-4ac
Δ = 0.00322-4·1·(-0.0016)
Δ = 0.00641024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0032)-\sqrt{0.00641024}}{2*1}=\frac{-0.0032-\sqrt{0.00641024}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0032)+\sqrt{0.00641024}}{2*1}=\frac{-0.0032+\sqrt{0.00641024}}{2}
$